A) Sulphurous acid
B) Pyrosulphuric acid
C) Dithionous acid
D) Thiosulphuric acid
Correct Answer: C
Solution :
Dithionous acid \[({{H}_{2}}{{S}_{2}}{{O}_{4}})\] has sulphur in +3 oxidation state. \[HO-\overset{O}{\mathop{\overset{||}{\mathop{S}}\,}}\,-\overset{O}{\mathop{\overset{||}{\mathop{S}}\,}}\,-OH\] ; \[2(+1)+2x+4(-2)=0\] \[2x=8-2=6\]; \[\overset{+4}{\mathop{Mn{{O}_{2}}}}\,+4HCl\,\to \overset{+2}{\mathop{MnC{{l}_{2}}}}\,+2{{H}_{2}}O+C{{l}_{2}}\]
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