A) \[S{{O}_{2}}\]
B) \[Mn{{O}_{2}}\]
C) \[A{{l}_{2}}{{O}_{3}}\]
D) \[Cr{{O}_{3}}\]
Correct Answer: A
Solution :
The minimum and maximum oxidation number of S are `2 and +6 respectively. Since the oxidation number of S in \[S{{O}_{2}}\] is +4, therefore it can be either increased or decreased. Therefore \[S{{O}_{2}}\] behaves both as an oxidising as well as reducing agent.
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