A) The solution turns blue
B) The solution is decolourised
C) \[S{{O}_{2}}\] is reduced
D) Green \[C{{r}_{2}}{{(S{{O}_{4}})}_{3}}\] is formed
Correct Answer: D
Solution :
\[{{K}_{2}}C{{r}_{2}}{{O}_{7}}+{{H}_{2}}S{{O}_{4}}+3S{{O}_{2}}\,\to \]\[{{K}_{2}}S{{O}_{4}}+\underset{\text{Green}}{\mathop{C{{r}_{2}}{{(S{{O}_{4}})}_{3}}}}\,+3{{H}_{2}}O\]
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