A) \[S+HCl+N{{a}_{2}}S\]
B) \[S+HCl+N{{a}_{2}}S{{O}_{4}}\]
C) \[S+HCl+N{{a}_{2}}S{{O}_{3}}\]
D) \[S+NaCl{{O}_{3}}+{{H}_{2}}O\]
Correct Answer: B
Solution :
\[N{{a}_{2}}{{S}_{2}}{{O}_{3}}+C{{l}_{2}}+{{H}_{2}}O\,\to \,N{{a}_{2}}S{{O}_{4}}+2HCl+S\]
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