A) \[{{H}_{2}}O\]
B) \[{{H}_{2}}S\]
C) \[{{H}_{2}}Te\]
D) \[{{H}_{2}}Se\]
Correct Answer: C
Solution :
The bond between \[({{H}_{2}}Te)\] is weakest hence it gives \[C{{l}_{2}}+{{H}_{2}}O\,\to \,2HCl+[O]\] ion easily.
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