10th Class Mathematics Pair of Linear Equations in Two Variables Question Bank Pair of Linear Equations in Two Variables

  • question_answer Read the statements carefully and state 'T' for true and 'F' for false.           
    (i) The pair of linear equations \[x+2y=5\]and \[7x+3y=13\] has unique solution\[x=2.\text{ }y=1\].                      
    (ii) \[\sqrt{2}x+\sqrt{3}y=0,\] \[\sqrt{3}x-\sqrt{8}y=0\] has no solution.
    (iii) The values of p and q for which the following system of equations \[2x-y=5,\] \[(p+q)x+(2p-q)y=15\]has infinite number of solutions, is \[p=1\]and\[q=5\].

    A)  i-T                   ii-F        iii-T

    B)  i-T                   ii-T       iii-F

    C)  i-F                   ii-T       iii-T

    D)  i-F                   ii-F       iii-T

    Correct Answer: D

    Solution :

    (i) Given equations are \[x+2y=5\]  ...(1) and  \[7x+3y=13\]        ...(2) Multiplying (1) by 7 and then subtracting from (2), we get \[7x+3y-7x-14y=13-35\] \[x=1\]and \[y=2\] Here, \[\frac{1}{7}\ne \frac{2}{3}\ne \frac{5}{13},\] a unique solution exist. (ii) Given equations are \[\sqrt{2}x+\sqrt{3}y=0\]  and \[\sqrt{3}x-\sqrt{8}y=0\] \[\frac{\sqrt{2}}{\sqrt{3}}\ne \frac{\sqrt{3}}{-2\sqrt{2}}\] \[\therefore \] Given equations have a unique solution (iii) Given equations are \[2x-y=5\]      .....(1) and \[(p+q)x+(2p-q)y=15\]            ?..(2) Putting \[p=1\]and \[q=5\]in (2), we get \[6x-3y=15\]  or  \[2x-y=5\]              .....(3) From (1) and (3), we have \[\frac{2}{2}=\frac{-1}{-1}=\frac{5}{5}\]  Hence, infinitely many solutions exist.

You need to login to perform this action.
You will be redirected in 3 sec spinner