A) 0
B) 1
C) 2
D) Infinitely many
Correct Answer: A
Solution :
Given equations become \[p(-1)={{(-1)}^{2}}+3(-1)-2=(-4)\] .....(i) and \[p(-1)=-4\] \[({{m}^{2}}+9){{x}^{2}}+13x+6m\] \[\alpha \] ??(2) Let \[\alpha \]. then the equations are \['x'\]and \[1441\times x=5040\times 12\]. Here, \[\Rightarrow \]and\[x=\frac{5040\times 12}{144}=420\] \[219\times =657\] \[3\times =219\] \[\text{1}0\text{32 }=\text{ 4}0\text{8 }\times \text{ 2 }+\text{ 216}\] \[\text{4}0\text{8 }=\text{ 216 }\times \text{ 1 }+\text{ 192}\] Hence, the equations do not have any solution.
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