A) \[\frac{1}{t}\]
B) t
C) ?t
D) \[-\frac{1}{t}\]
Correct Answer: C
Solution :
Normal is \[y-2a{{t}_{1}}=\frac{-2at}{2a}(x-a{{t}^{2}})\] Therefore, slope \[\Rightarrow \].You need to login to perform this action.
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