A) \[y={{m}^{2}}x-2mx-a{{m}^{3}}\]
B) \[{{m}^{3}}y={{m}^{2}}x-2a{{m}^{2}}-a\]
C) \[{{m}^{3}}y=2a{{m}^{2}}-{{m}^{2}}x+a\]
D) None of these
Correct Answer: C
Solution :
\[y-\frac{2a}{m}=-\frac{2a/m}{2a}\left( x-\frac{a}{{{m}^{2}}} \right)\] Þ \[y-\frac{2a}{m}=\frac{-1}{m}\left( x-\frac{a}{{{m}^{2}}} \right)\] Þ \[{{m}^{3}}y+{{m}^{2}}x-2a{{m}^{2}}-a=0\].You need to login to perform this action.
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