A) \[-16\]
B) \[-8\]
C) \[-24\]
D) 24
Correct Answer: D
Solution :
\[y=-2x-k\]is normal to \[{{y}^{2}}=-8x\] or \[-k=-\{-4(-2)-2{{(-2)}^{3}}\}=-(8+16)\]Þ \[\Rightarrow \,\frac{5}{3}=\frac{5}{2}({{e}^{2}}-1)\].You need to login to perform this action.
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