question_answer

In a parallelogram ABCD, diagonal AC measures 34 m and the perpendicular distance of AC from either of the vertices B and D is 12 m. Area of parallelogram is

A)  \[204\text{ }{{m}^{2}}\]               

B)  \[408\text{ }{{\text{m}}^{2}}\]     

C)         \[816\,{{m}^{2}}\]        

D)         \[402\,{{m}^{2}}\]             

Correct Answer: B

Solution :

        Area of parallelogram ABCD = Area of \[\Delta ADC\]+ Area of \[\Delta ABC\]                         \[=\frac{1}{2}\times 34\times 12+\frac{1}{2}\times 34\times 12\] \[=204+204=408\text{ }{{m}^{2}}\]