A) \[6\frac{1}{2}cm\]
B) \[6\,cm\]
C) \[6\frac{2}{3}\,cm\]
D) \[6\frac{3}{4}\,cm\]
Correct Answer: C
Solution :
Here we equate the areas, i.e., \[AB\times DL=BC\times DM\] \[\Rightarrow \] \[18\times DL=12\times 10\] \[\Rightarrow \] \[DL=\frac{12\times 10}{18}=\frac{20}{3}=6\frac{2}{3}cm\]You need to login to perform this action.
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