| Column I | Column II |
| (a) Highest electronegativity | (i) Caesium |
| (b) Highest electron affinity | (ii) Ruthennium |
| (c) Highest electropositivity | (iii) Fluorine |
| (d) Highest oxidation number | (iv) Chlorine |
A) (a) - (i), (b) - (ii), (c) - (iii), (d) - (iv)
B) (a) - (ii), (b) - (iii), (c) - (iv), (d) - (i)
C) (a) - (iii), (b) - (iv), (c) - (i), (d) - (ii)
D) (a) - (iv), (b) - (i), (c) - (ii), (d) - (iii)
Correct Answer: C
Solution :
Fluorine being a non-metal and smaller in size, has the highest electronegativity. Chlorine has highest electron affinity than fluorine due to interelectronic repulsions between the added electron and the other electrons in the electron cloud of small sized F atom. Caesium has highest electropositivity as it is an alkali metal having large atomic size and high metallic character. Ruthenium being a transition element shows highest oxidation number.
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