JEE Main & Advanced Physics Ray Optics Question Bank Photometry

  • question_answer
    If luminous efficiency of a lamp is 2 lumen/watt and its luminous intensity is 42 candela, then power of the lamp is [AFMC 1998]

    A)            62 W                                        

    B)            76 W                  

    C)            138 W                                      

    D)            264 W

    Correct Answer: D

    Solution :

                       Luminous flux\[=4\pi \ L\]\[=4\times 3.14\times 42\ =\ 528\]Lumen Power of lamp \[=\frac{\text{Luminous}\ \text{flux}}{\text{Luminous}\,\text{efficiency}}\]\[=\frac{528}{2}=264\ W\]


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