A) \[\frac{1}{3}\]
B) \[\frac{16}{27}\]
C) \[\frac{1}{4}\]
D) \[\frac{1}{9}\]
Correct Answer: A
Solution :
Case I \[{{I}_{A}}=\frac{100}{{{2}^{2}}}=25\ cd\] and \[{{I}_{B}}=\frac{100}{{{(2.5)}^{2}}}\cos \theta \] \[=\frac{100}{{{2.5}^{2}}}\times \frac{2}{2.5}\]\[=\frac{200}{{{(2.5)}^{3}}}\] Case II, \[I{{'}_{B}}=X\,{{I}_{B}}=\frac{25}{{{(3.25)}^{3/2}}}\] so \[\frac{I{{'}_{B}}}{{{I}_{B}}}=\frac{25}{200}\times \frac{{{(2.5)}^{3}}}{{{(3.25)}^{3/2}}}\] \[\Rightarrow X=1/3\]You need to login to perform this action.
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