A) (1 / 9) times
B) (1 / 3) times
C) 3 times
D) 9 times
Correct Answer: A
Solution :
\[I\propto \frac{1}{{{r}^{2}}}\]\[\Rightarrow \frac{{{I}_{2}}}{{{I}_{1}}}=\frac{r_{1}^{2}}{r_{2}^{2}}\]\[=\frac{{{60}^{2}}}{{{180}^{2}}}=\frac{1}{9}\]
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