A) 1256 lumen
B) 1600 lumen
C) 100 candela
D) 400 lumen
Correct Answer: A
Solution :
\[I=\frac{L}{{{r}^{2}}}\]\[\Rightarrow L=I.{{r}^{2}}\]\[=22\times {{2}^{2}}=100\] Now \[\varphi =4\pi \,L=4\times 3.14\times 100\]= 1256 lumen.You need to login to perform this action.
You will be redirected in
3 sec