A) \[6C{{O}_{2}}+6{{H}_{2}}O\underset{\text{Chlorophyll}}{\mathop{\xrightarrow{\text{Light}}}}\,{{C}_{2}}{{H}_{12}}{{O}_{6}}+6{{O}_{2}}\]
B) \[6C{{O}_{2}}+12{{H}_{2}}O\underset{\text{Chlorophyll}}{\mathop{\xrightarrow{\text{Light}}}}\,{{C}_{6}}{{H}_{12}}{{O}_{6}}+6{{H}_{2}}O+6{{O}_{2}}\]
C) \[12C{{O}_{2}}+6{{H}_{2}}O\underset{\text{Chlorophyll}}{\mathop{\xrightarrow{\text{Light}}}}\,2{{C}_{6}}{{H}_{12}}{{O}_{6}}+6{{O}_{2}}\]
D) None of the above
Correct Answer: B
Solution :
Photosynthesis reaction shows that "formation of carbohydrates from\[C{{O}_{2}}\]and\[{{H}_{2}}O\]by illuminated green cells of plants,\[{{O}_{2}}\]and \[{{H}_{2}}O\]are the bye products.
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