A) \[ab'=a'b\]
B) \[ab=a'b'\]
C) \[aa'=bb'\]
D) \[{{a}^{2}}+{{b}^{2}}=1\]
Correct Answer: A
Solution :
\[\frac{a-{a}'-{a}'}{{a}'-a}=\frac{b-{b}'-{b}'}{{b}'-b}\] \[\Rightarrow \,\,\,\frac{a-2{a}'}{{a}'-a}=\frac{b-2{b}'}{{b}'-b}\]\[\Rightarrow \,\,\frac{a}{{{a}'}}=\frac{b}{{{b}'}}\,\,\Rightarrow \,\,a{b}'={a}'b.\]You need to login to perform this action.
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