JEE Main & Advanced Physics Wave Optics / तरंग प्रकाशिकी Question Bank Polarisation of Light

  • question_answer
    A light has amplitude A and angle between analyser and polariser is 60°. Light is reflected by analyser has amplitude       [UPSEAT 2001]

    A)            \[A\sqrt{2}\]                        

    B)            \[A/\sqrt{2}\]

    C)            \[\sqrt{3}A/2\]                    

    D)            \[A/2\]

    Correct Answer: D

    Solution :

               The amplitude will be\[A\cos {{60}^{o}}=A/2\]


You need to login to perform this action.
You will be redirected in 3 sec spinner