A) \[3\times {{10}^{8}}\]
B) \[\left( \frac{3}{\sqrt{2}} \right)\times {{10}^{8}}\]
C) \[\sqrt{3}\times {{10}^{8}}\]
D) \[0.5\times {{10}^{8}}\]
Correct Answer: C
Solution :
From Brewster's law \[\mu =\tan \,{{i}_{p}}\]Þ \[\frac{c}{v}=\tan 60{}^\circ =\sqrt{3}\] Þ \[v=\frac{c}{\sqrt{3}}=\frac{3\times {{10}^{8}}}{\sqrt{3}}=\sqrt{3}\times {{10}^{8}}\]m/sec.
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