JEE Main & Advanced Physics Wave Optics Question Bank Polarisation of Light

  • question_answer The angle of polarization for any medium is 60o, what will be critical angle for this                                              [UPSEAT 1999]

    A)            \[{{\sin }^{-1}}\sqrt{3}\]  

    B)            \[{{\tan }^{-1}}\sqrt{3}\]

    C)            \[{{\cos }^{-1}}\sqrt{3}\] 

    D)            \[{{\sin }^{-1}}\frac{1}{\sqrt{3}}\]

    Correct Answer: D

    Solution :

                       By using \[\mu =\tan {{\theta }_{p}}\Rightarrow \mu =\tan 60=\sqrt{3}\], also \[C={{\sin }^{-1}}\left( \frac{1}{\mu } \right)\Rightarrow C={{\sin }^{-1}}\left( \frac{1}{\sqrt{3}} \right)\]


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