A) \[{{\sin }^{-1}}\sqrt{3}\]
B) \[{{\tan }^{-1}}\sqrt{3}\]
C) \[{{\cos }^{-1}}\sqrt{3}\]
D) \[{{\sin }^{-1}}\frac{1}{\sqrt{3}}\]
Correct Answer: D
Solution :
By using \[\mu =\tan {{\theta }_{p}}\Rightarrow \mu =\tan 60=\sqrt{3}\], also \[C={{\sin }^{-1}}\left( \frac{1}{\mu } \right)\Rightarrow C={{\sin }^{-1}}\left( \frac{1}{\sqrt{3}} \right)\]
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