A) \[-\left( {{b}^{2}}+ac \right),bc\]
B) \[\left( -\frac{b}{a}\And \frac{c}{b} \right)\]
C) \[\left( \frac{{{b}^{2}}+ac}{a},\frac{bc}{b} \right)\]
D) \[\left( -\frac{b}{c}\And \frac{c}{a} \right)\]
Correct Answer: D
Solution :
(d): Mind of a mathematician By observation \[(\alpha +\beta )=-\left( \frac{b}{a}+\frac{c}{b} \right)\] \[\alpha \beta =\frac{b}{a}\times \frac{c}{b}\] This implies \[\alpha =\left( -\frac{b}{a} \right)\]and \[\beta =\left( -\frac{c}{b} \right)\]
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