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10th Class Mathematics Polynomials Question Bank Polynomial

  • question_answer
    For what values of k is one zero of the polynomial\[\left( {{k}^{2}}-16 \right){{x}^{2}}+9x+6k,\] the reciprocal of the other?

    A)   \[9,\,0\]                       

    B)  \[-3,-6\]        

    C)  \[-9,0\]            

    D)  \[8,-2\]

    Correct Answer: D

    Solution :

    (d): \[\alpha ,\frac{1}{\alpha }\Rightarrow \alpha +\frac{1}{\alpha }=\frac{-9}{{{k}^{2}}-16}\]  and \[1=\frac{6k}{{{k}^{2}}-16}\Rightarrow {{k}^{2}}-16-6k=0\]: Solve this quadratic


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