A) \[\left( 2a-1 \right)\left( 2a+1 \right)\]
B) \[\left( 2a-1 \right)\left( 1-2a \right)\]
C) \[\left( 2a+1 \right)\left( 2a+1 \right)\]
D) \[\left( 2a- \right)\left( 2a-1 \right)\]
Correct Answer: D
Solution :
(d) \[4{{a}^{2}}-4a+1={{(2a)}^{2}}-2.2a.1+{{1}^{2}}\] \[={{\left( 2a-1 \right)}^{2}}=\left( 2a-1 \right)\left( 2a-1 \right)\]You need to login to perform this action.
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