A) 0
B) \[x+y\]
C) \[{{x}^{2}}-{{y}^{2}}\]
D) \[2{{y}^{4}}\]
Correct Answer: A
Solution :
Let \[f(x)={{x}^{4}}-{{y}^{4}}\]and \[g(x)=x-y\] Now, \[g(x)=0\Rightarrow x-y=0\Rightarrow x=y\] \[\therefore \]By remainder theorem, we know that when \[f(x)\]is divided by \[g(x).\]then the remainder is \[f(y).\] Now, \[f(y)={{y}^{4}}-{{y}^{4}}=0\]You need to login to perform this action.
You will be redirected in
3 sec