A) 0
B) a
C) -a
D) 2a
Correct Answer: C
Solution :
We have, \[p(x)={{x}^{3}}+a{{x}^{2}}+2x+\] By remainder theorem, we know that when \[p(x)\]is divided by \[(x+a).\]then the remainder is \[(p-a).\]Now, \[p(-a)={{(-a)}^{3}}+a{{(-a)}^{2}}+2(-a)+a\] \[=-{{a}^{3}}+{{a}^{3}}-2a+a=-a\]You need to login to perform this action.
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