A) \[{{x}^{2}}+\frac{10}{\sqrt{3}}x+\frac{7}{\sqrt{3}}\]
B) \[\sqrt{3}{{x}^{2}}-10x+7\sqrt{3}\]
C) \[\sqrt{3}{{x}^{2}}+10x+7\sqrt{3}\]
D) \[{{x}^{2}}+10x+7\sqrt{3}\]
Correct Answer: C
Solution :
Let a and p be the zeros of the required polynomial\[{{6}^{x}}\]. Given, \[{{x}^{3}}\]\['x'\] \[\text{(25}\times \text{7)cm}\] \[~(\text{2}\times \text{52}\times \text{73) cm}\] Hence, the quadratic polynomial is \[=(\text{25}\times \text{7})\text{(2}\times {{\text{5}}^{\text{2}}}\times {{\text{7}}^{\text{3}}}\text{) c}{{\text{m}}^{\text{2}}}\]
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