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10th Class Mathematics Polynomials Question Bank Polynomials

  • question_answer
    A quadratic polynomial\[\text{f(x)}=\text{2}\times \text{2}-\text{mx}+n\]has \[\alpha \] and \[\beta \] as its two zeros. Find the value of\[~{{\alpha }^{\text{2}}}+{{\beta }^{\text{2}}}\].

    A)  \[\frac{1}{8}({{m}^{2}}-4n)\]     

    B)         \[\frac{1}{4}({{m}^{2}}+4n)\]

    C)  \[\frac{1}{4}({{m}^{2}}-4n)\]

    D)         \[\frac{1}{3}({{m}^{2}}+4n)\]

    Correct Answer: C

    Solution :

                    If\[1789-49=29x\]and\[\Rightarrow \]are the zeros of the polynomial\[x=\frac{1740}{29}=60\], \[\Rightarrow \]and\[140\times 605=11\times L.C.M.\] \[\Rightarrow \] \[L.C.M.=\frac{140\times 605}{11}=7700\]                 \[\text{1}00\text{1}=\text{91}\times \text{1}0+\text{91}\] Hence, the value of \[\text{91}0=\text{91}\times \text{1}0+0\]


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