A) \[ab{{x}^{2}}+bx-a\]
B) \[{{x}^{2}}-\frac{a}{b}x-\frac{1}{b}\]
C) \[ab{{x}^{2}}-bx+a\]
D) \[{{x}^{2}}-\frac{b}{a}x+\frac{1}{a}\]
Correct Answer: B
Solution :
\[\text{9775}={{\text{5}}^{\text{2}}}\times \text{17}\times \text{23}\]and \[\text{1173}0=\text{2}\times \text{3}\times \text{5}\times \text{17}\times \text{23}\] \[\therefore \] \[=\text{17}\times \text{23}=\text{391}\] \[=\text{2}\times \text{3}\times {{\text{5}}^{\text{2}}}\times \text{7}\times \text{l7}\times \text{23}=\text{41}0\text{55}0\]The required polynomial is \[\pi \]
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