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JEE Main & Advanced Physics Question Bank Prism Theory and Dispersion of Light

  • question_answer
    The refractive index of a prism for a monochromatic wave is \[\sqrt{2}\] and its refracting angle is 60°. For minimum deviation, the angle of incidence will be [MNR 1998; MP PMT 1989, 92, 2002; CPMT 1993, 2004]

    A)            30°

    B)            45°

    C)            60°

    D)            75°

    Correct Answer: B

    Solution :

                       \[\mu =\frac{\sin i}{\sin A/2}\]\[\Rightarrow \sqrt{2}=\frac{\sin i}{\sin \left( \frac{60}{2} \right)}\]            \[\Rightarrow \sqrt{2}\times \sin 30=\sin i\]\[\Rightarrow i={{45}^{o}}\]


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