A) 0.034 and 0.064
B) 0.064 and 0.034
C) 1.00 and 0.064
D) 0.034 and 1.0
Correct Answer: A
Solution :
The dispersive power for crown glass \[\omega =\frac{{{n}_{v}}-{{n}_{r}}}{{{n}_{y}}-1}\] = \[\frac{1.5318-1.5140}{(1.5170-1)}=\frac{0.0178}{0.5170}=0.034\] and for flint glass \[{\omega }'=\frac{1.6852-1.6434}{(1.6499-1)}=0.064\]
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