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JEE Main & Advanced Physics Question Bank Prism Theory and Dispersion of Light

  • question_answer
    A light ray is incident upon a prism in minimum deviation position and suffers a deviation of 34°.  If the shaded half of the prism is knocked off, the ray will     [MP PMT 1992]

    A)            Suffer a deviation of 34° 

    B)            Suffer a deviation of 68°

    C)            Suffer a deviation of 17° 

    D)            Not come out of the prism

    Correct Answer: C

    Solution :

                       By formula \[\delta =(n-1)A\Rightarrow 34=(n-1)A\] and in the second position \[{\delta }'=(n-1)\frac{A}{2}\]            \[\therefore \] \[\frac{34}{{{\delta }'}}=\frac{(n-1)A}{(n-1)\frac{A}{2}}\] or \[{\delta }'=\frac{34}{2}={{17}^{o}}\]


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