question_answer

Angle of deviation \[(\delta \]) by a prism (refractive index = \[\mu \] and supposing the angle of prism A to be small) can be given by                                                                  [MP PMT 1994]

A)            \[\delta =(\mu -1)\,A\]   

B)            \[\delta =(\mu +1)\,A\]

C)            \[\delta =\frac{\sin \frac{A+\delta }{2}}{\sin \frac{A}{2}}\]               

D)            \[\delta =\frac{\mu -1}{\mu +1}A\]