A) 30°
B) 45°
C) 60°
D) 75°
Correct Answer: C
Solution :
\[\mu =\frac{\sin \left( \frac{A+{{\delta }_{m}}}{2} \right)}{\sin \frac{A}{2}}\] Þ \[\sqrt{3}=\frac{\sin \left( \frac{60{}^\circ +{{\delta }_{m}}}{2} \right)}{\sin \frac{60{}^\circ }{2}}\] \[\Rightarrow \]\[\frac{\sqrt{3}}{2}\]=\[\sin \left( 30{}^\circ +\frac{{{\delta }_{m}}}{2} \right)\]\[\Rightarrow {{\delta }_{m}}={{60}^{o}}\]
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