A) \[\frac{1}{5}\]
B) \[\frac{2}{5}\]
C) \[\frac{3}{5}\]
D) \[\frac{4}{5}\]
Correct Answer: B
Solution :
(b): Total number of outcomes \[=5\times 4\times 3\times 2=120\] the number of favourable cases \[=(2\times 4\times 3\times 2)=48\] (i.e., odd number) The required probability \[=\frac{48}{120}=\frac{2}{5}\].You need to login to perform this action.
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