A) \[\frac{1}{2}\]
B) \[\frac{1}{4}\]
C) \[\frac{3}{4}\]
D) \[\frac{1}{8}\]
Correct Answer: C
Solution :
\[\text{S}=\{\text{HH},\text{ HT},\text{ TH},\text{ TT}\}\text{ }\Rightarrow \,\,\text{n(s)}=\text{4}\] \[\text{E}=\{\text{HT},\text{ TH},\text{ HH}\}\text{ }\Rightarrow \text{ n(E)}=\text{3}\] \[\therefore \]\[p(E)=\frac{n(E)}{n(S)}=\frac{3}{4}\]
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