A) \[\frac{1}{3}\]
B) \[\frac{1}{4}\]
C) \[\frac{1}{5}\]
D) \[\frac{1}{6}\]
Correct Answer: B
Solution :
(b) \[:n\left( E \right)=\left\{ l,4,9 \right\}~n\left( S \right)=\left\{ 1,\text{ }2,\text{ }3,........12 \right\}\] \[n(P)=\frac{3}{12}=\frac{1}{4}\]You need to login to perform this action.
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