A) \[\frac{1}{2}\]
B) \[\frac{7}{12}\]
C) \[\frac{1}{4}\]
D) \[\frac{1}{6}\]
Correct Answer: B
Solution :
(b): \[n\left( E \right)=\left\{ 4,6,8,9,10,12,14,15,16,18,20,21,22,24 \right\}\] \[n\left( S \right)=\left\{ 1,2,3,.........24 \right\}\] \[n\left( P \right)=\frac{14}{24}=\frac{7}{12}\]You need to login to perform this action.
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