• # question_answer Three unbiased coins are tossed. What is the probability of getting at least 2 heads? A)  $\frac{1}{4}$                                     B)  $\frac{1}{2}$C)  $\frac{1}{3}$                         D)  $\frac{1}{8}$

(b): Here $S=\{TTT,TTH,THT,HTT,THH,HTH,HHT,HHH\}$ Let E = event of getting at least two heads = x$\{THH,HTH,HHT,HHH\}.$ $\therefore p(E)=\frac{n(E)}{n(S)}=\frac{4}{8}=\frac{1}{2}$