A) \[\frac{1}{10}\]
B) \[\frac{2}{5}\]
C) \[\frac{2}{11}\]
D) \[\frac{5}{7}\]
Correct Answer: C
Solution :
(c): P (getting a prize) \[=\frac{10}{\left( 10+45 \right)}=\frac{10}{55}=\frac{2}{11}.\] Let E = event of getting a face card. Then, \[n\left( E \right)=12.\] \[\therefore p(E)=\frac{n(E)}{n(S)}=\frac{5}{200}=\frac{1}{40}\]You need to login to perform this action.
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