A) \[\frac{1}{2}\]
B) \[\frac{1}{3}\]
C) \[\frac{2}{3}\]
D) \[\frac{3}{4}\]
Correct Answer: D
Solution :
(d): Probability of 3 heads =1/8 Also, Probability of 3 tails=1/8. Required probability \[=1-(1/8+1/8)=6/8=3/4\].
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