A) \[\frac{11}{216}\]
B) \[\frac{5}{108}\]
C) \[\frac{9}{216}\]
D) \[12\frac{1}{18}\]
Correct Answer: B
Solution :
Total number of outcomes when three dice are thrown \[=6\times 6\times 6=216\] For sum of numbers to be 15, possible ways are, (6, 6, 3). (6, 3, 6), (3, 6, 6), (6, 5, 4), (6, 4, 5), (5, 4, 6), (5, 6, 4), (4, 5, 6), (4, 6, 5), (5, 5, 5) \[\therefore \] Number of favorable outcomes =10 \[\therefore \] Required probability \[=\frac{10}{216}=\frac{5}{108}\]You need to login to perform this action.
You will be redirected in
3 sec