A) Aw
B) w/k
C) dw/dk
D) x/t
Correct Answer: A
Solution :
Given \[y=A\sin (kx-\omega t)\] \[\Rightarrow \] \[v=\frac{dy}{dt}\]= \[-A\omega \cos (kx-\omega \,t)\]: Þ \[{{v}_{\max }}=A\omega \]
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