JEE Main & Advanced Physics Wave Mechanics Question Bank Progressive Waves

  • question_answer
    The equation of a transverse wave is given by                           \[y=10\sin \pi (0.01x-2t)\]            where x  and y are in cm and t is in second. Its frequency is [MP PET 1990; MNR 1986; RPET 2003]

    A)            \[10{{\sec }^{-1}}\]            

    B)            \[2\,{{\sec }^{-1}}\]

    C)            \[1\,{{\sec }^{-1}}\]           

    D)            \[0.01\,{{\sec }^{-1}}\]

    Correct Answer: C

    Solution :

               Comparing with the standard equation,                    \[y=A\sin \frac{2\pi }{\lambda }(vt-x)\], we have                    \[v=200\]\[cm/\sec \], \[\lambda =200\]\[cm\,;\]\[\therefore \]\[n=\frac{v}{\lambda }=1\]\[{{\sec }^{-1}}\]


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