A) \[3.6\times {{10}^{-11}}\]
B) \[3.6\times {{10}^{-6}}\]
C) \[3.6\times {{10}^{-4}}\]
D) 3.6
Correct Answer: C
Solution :
Maximum particle velocity \[{{v}_{\max }}=\omega a\] and wave velocity \[v=\frac{\omega }{k}\]Þ \[\frac{{{v}_{\max }}}{v}=\frac{\omega a}{\omega /k}=ka\]. From the given equation\[k=\text{Co-efficient}\ \text{of}\,x=6micron\]\[\ =6\times {{10}^{-6}}m\] Þ \[\frac{{{v}_{\max }}}{v}=ka=6\times {{10}^{-6}}\times 60=3.6\times {{10}^{-4}}\]
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