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JEE Main & Advanced Physics Wave Mechanics Question Bank Progressive Waves

  • question_answer
    The phase difference between two points separated by 0.8 m in a wave of frequency 120 Hz is \[{{90}^{o}}\]. Then the velocity of wave will be                                   [MH CET 1999]

    A)            192 m/s                                  

    B)            360 m/s

    C)            710 m/s                                  

    D)            384 m/s

    Correct Answer: D

    Solution :

               Path difference \[\Delta =\frac{\lambda }{2\pi }\times \varphi =\frac{\lambda }{2\pi }\times \frac{\pi }{2}=\frac{\lambda }{4}\] \[\because \,\Delta =0.8\,m\] Þ \[\frac{\lambda }{4}=0.8\,\]Þ l = 3.2 m. \ v = nl = 120 ´ 3.2 = 384 m/s


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