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JEE Main & Advanced Physics Wave Mechanics Question Bank Progressive Waves

  • question_answer
    The phase difference between two points separated by 0.8 m in a wave of frequency is 120 Hz is \[\frac{\pi }{2}.\] The velocity of wave is                                                      [Pb. PET 2000]

    A)            720 m/s                                  

    B)            384 m/s

    C)            250 m/s                                  

    D)            1 m/s

    Correct Answer: B

    Solution :

               Phase difference \[=\frac{2\pi }{\lambda }\]´ path difference                    \[\Rightarrow \frac{\pi }{2}=\frac{2\pi }{\lambda }\times 0.8\]\[\Rightarrow \lambda =4\times 0.8=3.2\,m\]                    Velocity \[v=n\lambda \]\[=120\times 3.2=384\,m/s.\]


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