A) \[a\]
B) 0
C) \[{{a}^{2}}\]
D) \[{{2}^{n}}\]
Correct Answer: B
Solution :
L.H.S. =\[a[{{C}_{0}}-{{C}_{1}}+{{C}_{2}}-{{C}_{3}}+...{{(-1)}^{n}}.{{C}_{n}}]\]\[+[{{C}_{1}}-2{{C}_{2}}+3{{C}_{3}}-....+{{(-1)}^{n-1}}n.{{C}_{n}}]\] \[=a.0+0=0\]
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