A) 0
B) 2
C) 1/2
D) 1
Correct Answer: D
Solution :
\[I=\int_{0}^{2}{|x-1|dx=\int_{0}^{1}{(-x+1)dx+\int_{1}^{2}{(x-1)\,dx}}}\] \[=\left( \frac{-{{x}^{2}}}{2}+x \right)_{0}^{1}+\left( \frac{{{x}^{2}}}{2}-x \right)_{1}^{2}=1.\]
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